Key examples — thermodynamics

Where the chapter’s machinery shows up across the bookshelf.

Example 1: Laplace’s adiabatic correction to the speed of sound

Newton’s 1687 calculation of the speed of sound assumed isothermal compression: cN=p/ρ280m/sc_\text{N} = \sqrt{p/\rho} \approx 280\,\text{m/s} — about 15% below the measured 343 m/s. The discrepancy lasted 130 years. Laplace’s 1816 fix was to recognise that acoustic compressions are too fast for heat to conduct away, so they are adiabatic — and the slope (p/ρ)s(\partial p/\partial \rho)_s is larger than (p/ρ)T(\partial p/\partial \rho)_T by the factor γ=1.4\gamma = 1.4. The corrected speed c=γp/ρ343m/sc = \sqrt{\gamma p/\rho} \approx 343\,\text{m/s} agrees with experiment. See Sound Ch 4.4.

Example 2: polytropic gas inside an oscillating bubble

The gas inside a Rayleigh–Plesset bubble oscillates between compression and rarefaction at frequencies up to MHz. Whether the compression is isothermal (κ=1\kappa = 1) or adiabatic (κ=γ\kappa = \gamma) depends on the dimensionless ratio ωR2/αg\omega R^2/\alpha_g, where αg\alpha_g is the gas thermal diffusivity. For a 1 μm bubble in air at ω=107rad/s\omega = 10^7\,\text{rad/s}, this ratio is order unity, and κ\kappa sits at an intermediate frequency-dependent value κ(ω)\kappa(\omega) that the Cavitation book’s bubble-contents chapter develops. The polytropic envelope from the chapter is what makes this analysis tractable.

Example 3: enthalpy across a shock front

The Rankine–Hugoniot energy condition across a shock — derived from open-system conservation of mass, momentum, and energy with the shock as a control volume — is

h1+12u12  =  h2+12u22,h_1 + \tfrac12 u_1^2 \;=\; h_2 + \tfrac12 u_2^2,

where hh is the specific enthalpy and uu the flow velocity. The two states 11 and 22 are upstream and downstream of the shock. Enthalpy enters precisely because the shock is an open control volume — the flow-work term that closed-system UU would miss is exactly the pVpV Legendre-transform that turns UU into hh. See Sound Ch 10.5.

Example 4: γ from molecular structure of air

Air at room temperature has γ=7/5=1.4\gamma = 7/5 = 1.4, not 5/35/3 (monatomic) or 9/79/7 (full diatomic with vibrations). This is the equipartition counting from the chapter: N₂ and O₂ molecules have three translational + two rotational degrees of freedom active, but vibrational modes are frozen out by quantum statistics (the vibrational quantum exceeds kBTk_B T at room temperature). γ=(f+2)/f=7/5\gamma = (f + 2)/f = 7/5 for f=5f = 5. The Sound book’s molecular-relaxation chapter develops the consequences for sound absorption when vibrational modes start to thaw at high frequencies.

Example 5: heat capacity of water

Liquid water has cp4.18J/(g⋅K)c_p \approx 4.18\,\text{J/(g·K)} — roughly four times higher than most other liquids. This unusually large heat capacity comes from the vibrational degrees of freedom of hydrogen bonds (which are at energies comparable to kBTk_B T at room temperature, unlike covalent bonds), plus librations of the molecular rotation, plus the usual translational and rotational classical degrees of freedom. The combined active-DOF count is much higher than for a simpler liquid. This anomalously high cpc_p is what makes water such an effective thermal buffer in climate and physiology. The intermolecular-forces chapter develops the hydrogen-bond picture.