3.5 Standing waves and modes

A string of length LL clamped at both ends. Apply boundary conditions y(0,t)=y(L,t)=0y(0, t) = y(L, t) = 0 to the general d’Alembert solution. The only consistent steady oscillations are sinusoidal, with spatial profile

yn(x,t)  =  Ansin ⁣(nπxL)cos(ωnt+φn),y_n(x, t) \;=\; A_n \sin\!\left( \frac{n \pi x}{L} \right) \cos(\omega_n t + \varphi_n),

with n=1,2,3,n = 1, 2, 3, \ldots and

ωn  =  nπcL,fn  =  ωn2π  =  nc2L.\omega_n \;=\; \frac{n \pi c}{L}, \qquad f_n \;=\; \frac{\omega_n}{2\pi} \;=\; \frac{n c}{2 L}.

These are the modes (or normal modes, or harmonics) of the clamped string. The lowest is the fundamental (n=1n = 1); higher nn are overtones.

Why the modes are sinusoidal and the frequencies are $n c / 2L$

Look for a solution by separation of variables: y(x,t)=X(x)T(t)y(x, t) = X(x) T(t). The wave equation becomes

T¨c2T=XX=k2,\frac{\ddot T}{c^2 T} = \frac{X''}{X} = -k^2,

a separation constant we name k2-k^2. The spatial equation X+k2X=0X'' + k^2 X = 0 has solution X(x)=Asin(kx)+Bcos(kx)X(x) = A \sin(k x) + B \cos(k x). Boundary condition X(0)=0X(0) = 0 kills the cosine (B=0B = 0); X(L)=0X(L) = 0 forces sin(kL)=0\sin(kL) = 0, i.e. kL=nπk L = n\pi for n=1,2,3,n = 1, 2, 3, \ldots. So kn=nπ/Lk_n = n\pi/L and ωn=ckn=nπc/L\omega_n = c k_n = n\pi c / L.

The time equation T¨+ωn2T=0\ddot T + \omega_n^2 T = 0 gives T(t)=Ancos(ωnt)+Bnsin(ωnt)T(t) = A_n \cos(\omega_n t) + B_n \sin(\omega_n t).

Standing waves as superposed travelling waves

A mode can be written as a sum of two travelling waves of equal amplitude going opposite ways:

sin(kx)cos(ωt)  =  12[sin(kxωt)+sin(kx+ωt)].\sin(k x) \cos(\omega t) \;=\; \tfrac12 \big[\sin(k x - \omega t) + \sin(k x + \omega t)\big].

A standing wave is what you get when an equal-amplitude right-goer and left-goer interfere everywhere. Where they’re always in phase you get an antinode (maximum amplitude); where they’re always out of phase you get a node (zero amplitude). For mode nn on a clamped string, there are n+1n + 1 nodes (including the two endpoints) and nn antinodes between them.

The general motion

Because the wave equation is linear, any motion of the clamped string is a superposition of modes:

y(x,t)  =  n=1Ansin ⁣(nπxL)cos(ωnt+φn).y(x, t) \;=\; \sum_{n=1}^{\infty} A_n \sin\!\left( \frac{n\pi x}{L} \right) \cos(\omega_n t + \varphi_n).

This is a Fourier series in space at each instant. The amplitudes AnA_n and phases φn\varphi_n are fixed by initial conditions and are projections of the initial profile onto each mode shape — an integral with sin(nπx/L)\sin(n\pi x / L) as the weighting function.

Why this matters

Two things to carry forward:

  1. Sound in a tube is going to be the same story. The wave equation governs the acoustic pressure; clamped/free boundaries at the tube ends pick a discrete set of allowed frequencies; the general motion is a Fourier sum. Chapter 7 lesson 6 makes the swap explicit.
  2. A musical string plays a fundamental at f1=c/2Lf_1 = c/2L plus harmonics at integer multiples. The integer-harmonic spacing is the reason plucked-string and bowed-string instruments sound “musical”: their overtone series is consonant. The same integer spacing appears in any 1-D medium with equal boundary conditions on both ends.

Looking ahead

We have, in this chapter, derived a real wave equation from coupled oscillators, solved it explicitly, handled boundaries, and built standing waves. The wave equation we have is for transverse displacement on a string. The wave equation we want — for pressure perturbations in air — has exactly the same mathematical form but a different physical content. Chapter 4 derives that equation, four different ways, and the rest of the book is its consequences.